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ProfessorFilostrato
06-05-2005, 02:54 PM
Could someone help me simplify the square root of 98/27?

tkhunny
06-05-2005, 03:13 PM
Could someone help me simplify the square root of 98/27?
Prime Factorization will ALWAYS assist with these.

27 = 3^3 = (3^2)*3 <== I'm looking for perfect squares.
98 = 2*(7^2)

sqrt(98/27) = sqrt([2*(7^2)]/[(3^2)*3]) = (7/3)*sqrt(2/3)

ProfessorFilostrato
06-05-2005, 09:05 PM
Okay...lemme see of I understand you right....my final answer would be 7/3 times the sqrt of (2/3)?

tkhunny
06-05-2005, 10:07 PM
my final answer would be 7/3 times the sqrt of (2/3)?
It is possible that you will be required to rationalize the denominator. Personally, I don't consider that a necessary part of "simplify", but not everyone agrees with me.

(7/3)*sqrt(2/3) = (7/3)*sqrt(2/3)*sqrt(3/3) = (7/3)*sqrt(6/9) = (7/3)*(1/3)*sqrt(6) = (7/9)*sqrt(6)