PDA

View Full Version : Geometry Angle Degrees NEED HELP



08-30-2005, 12:37 PM
Okay, I'm not sure how I'm really going to explaing this problem, but I'll try. It's really confusing, and I'm not sure that I understand it correctly.



106' F
65'
D A

27' O 62'
E
C
B

It's a circle, O being the midpoint, and A, B, C, D, F are points on the circle. E is the intersection of C-F and B-D, the other chords are D-A, A-O, B-O. The (') stands for degrees, since I can't find a degree sign anywhere on my keyboard.

I hope that this makes sense, ask if if doesn't.

Now for the actual problem. I have to find:

m/BOA =
m/BDA=
m/DEF=

I would think, BOA would be 62', BDA = 62', and DEF = 106'. Apart from the fact that that seems too easy, BOA and BDA are totally different angles. How can they be the same measurment? But on the other hand, I have no clue how to solve it if that's the case.

Anyone know? I'd appreciate the help!

Denis
08-30-2005, 03:37 PM
WHY do you need to FIND angle BOA? It is GIVEN as 62 degrees according to your diagram.

NO, angle BDA is NOT 62 degrees...

Did you draw a circle, and draw the lines with the exact degrees as shown?
Angle BOC = 360 - 65 - 62 - 27 - 106 = 100 degrees.

Go draw Becky me girl...