Overlapping right triangles

[Richay]

http://img335.imageshack.us/img335/2871/overlappers71ki.jpg

Find A, B, and C. The segments that look perpendicular are perpendicular. Answer in the form: A, B, C (Round to the nearest tenth.)

I just want the equation...to solve it. Since i don't know what it is or how to get it.

And the equation for this one too.

http://img335.imageshack.us/img335/8940/overlappers92tn.jpg

Find a (top left) b (far left side) and c. Answer in the form a, b, c


Thanks for any help.

[TchrWill]

Find A, B, and C. The segments that look perpendicular are perpendicular. Answer in the form: A, B, C (Round to the nearest tenth.)

I just want the equation...to solve it. Since i don't know what it is or how to get it.

Due to similar triangles:

C/12 = 4/7

A/7 = (A + B/12

B/5 = C/4

Can you take it from here?

The next one can be done in the same way.

And the equation for this one too.

http://img335.imageshack.us/img335/8940/overlappers92tn.jpg

Find a (top left) b (far left side) and c. Answer in the form a, b, c


Thanks for any help.[/quote]