View Full Version : Another Vertical motion problem

06-06-2006, 07:28 PM
Sorry - I am going to flunk this course!

Same criteria:
The formula for the vertical motion of an object is:

h = -16t^2 + vt + s,
. . ."h" is the height (in feet) at a given time
. . ."s" is the initial height (in feet)
. . ."t" is the time in motion (in seconds)
. . ."v" is the initial velocity (in feet per second)

In the model, the coefficient of t^2 is one half of the acceleration due to gravity. On the surface of the earth this acceleration is approx 32 ft per second.

However in this problem this is on the moon - the acceleration due to gravity on the moon is only 16 ft per second. If a rocket takes off frin the moon with an ititial velocity of 90 ft per second and from a height of 2 ft how high will the rocket be after 5 minutes of flight?

06-06-2006, 08:12 PM
The replies to this exercise will be similar to the other one you posted: A rocket does not obey the posted formula, and the time is not appropriate to the exercise. Either the formula, or else the nature of the object, or else the time, or else some combination thereof, is incorrect.