View Full Version : Percentage calculation: which number 12% will be added....

santos

06-20-2006, 04:50 AM

Hi.

I need help regarding below mentioned queries.

How could i calculate, In which NUMBER (number unknown) 12%(percentage known) will be added to get the resulting 2400 (known number).

Thanks

TchrWill

06-20-2006, 08:41 AM

How could i calculate, In which NUMBER (number unknown) 12%(percentage known) will be added to get the resulting 2400 (known number).

X += .12X = 2400

1.12X == 2400

X = 2000

jonboy

06-20-2006, 02:36 PM

Uhh I think it would be more like this if I understand you q correctly:

\frac{.12x}{.12}=\frac{2400}{.12}

x=20,000

Check:

(20,000)(.12)=2400

skeeter

06-20-2006, 04:49 PM

well ... here's a third response for you. you'll have to be the judge on which one of us interpreted your problem correctly.

In which NUMBER (number unknown) 12%(percentage known) will be added to get the resulting 2400 (known number).

let x = the unknown number

x + (12% of x) = 2400

x + .12x = 2400

x(1 + .12) = 2400

x(1.12) = 2400

x = 2400/1.12 = 2142.86 (rounded to two decimal places)

Denis

06-20-2006, 06:24 PM

...may I have the envelope please... :roll:

stapel

06-20-2006, 09:08 PM

...may I have the envelope please... :roll:

This is why it's so important (hint, hint!) to include the full and exact statement of the exercise, and the complete instructions. It is difficult to assist in finding the answer when we are befuddled as to what the actual question is. :shock:

Eliz.

santos

06-21-2006, 08:33 AM

Thank u very much everybody for helping instantly.

Thanks :lol:

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