nae

06-20-2006, 09:16 PM

could someone please let me know if this is right.

y(y-4)=0

(y-2) (y+2)

y-2+2=0+2 y=2-2=0-2

y= 2, -2

y(y-4)=0

(y-2) (y+2)

y-2+2=0+2 y=2-2=0-2

y= 2, -2

View Full Version : what is the solution set of the following

nae

06-20-2006, 09:16 PM

could someone please let me know if this is right.

y(y-4)=0

(y-2) (y+2)

y-2+2=0+2 y=2-2=0-2

y= 2, -2

y(y-4)=0

(y-2) (y+2)

y-2+2=0+2 y=2-2=0-2

y= 2, -2

stapel

06-20-2006, 09:51 PM

To check the solutions to any "solving" exercise, plug them back into the original problem. If they work, then this suggests that they are correct.

You appear to have posted two different equations:

. . . . .y(y - 4) = 0

. . . . .(y - 2)(y + 2) = 0

Your solutions will work in one of the equations, but not in the other. Are you requesting assistance with the other...?

Thank you.

Eliz.

You appear to have posted two different equations:

. . . . .y(y - 4) = 0

. . . . .(y - 2)(y + 2) = 0

Your solutions will work in one of the equations, but not in the other. Are you requesting assistance with the other...?

Thank you.

Eliz.

nae

06-20-2006, 10:07 PM

I got it thank you.

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