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View Full Version : Some problems that I would like help in (triangles, etc)

Paulinaaa
06-21-2006, 03:12 PM
Hi I wanted to know if anyone can help me with these questions..I tried them but some of them I got wrong so I would like to review it with some of you.

1: A piece of paper 11 inches long is ripped into 3 pieces. The first piece is 3 inches more that twice the third piece. The second piece is 3 times the length of the third piece. What is the length of the second piece?

choices: 1 1/3 inches, 3 inches, 4 inches, 6 inches

10: A flag on a golf course is in the shape of a right triangle. The area of the flag is 156 square inch and its base is 12 inch, find the height of the flag.

choices: 12 inches, 13 inches, 22 inches, 26 inches

11: Angles A and B are complementary angles because their sum is 90 degrees. The measure of angle A is six degrees more than two times the measure of angle B. Find the measure of angle B.

choices: 42°, 30 °, 28°, 22°

14: A class is planning a trip to the Aquarium. They have saved $567 during the year for their annual field trip. Student tickets cost$12 and non-student tickets cost $15. If the number of students visiting the aquarium must be four times the number of non-student chaperones, how many students can visit the museum? choices: 9, 25, 36, 40 15: Kim and Deb ride bicycles in opposite directions. Deb's speed is three miles per hour faster than Kim. If they are 16.5 miles apart in 1.5 hours, what is the speed of Kim? choices: 4 mph, 5 mph, 7 mph, 9 mph happy 06-21-2006, 03:13 PM Don't post a list of problems without showing any work. Paulinaaa 06-21-2006, 03:22 PM umm..I did the work..but Im not gonna do it all over again. pka 06-21-2006, 03:27 PM umm..I did the work..but Im not gonna do it all over again. That may be why you have not done so well in class. Mathematics is easy to learn. It just takes a lot of work. If you do not want to work at it, you will not do well. stapel 06-21-2006, 03:47 PM umm..I did the work..but Im not gonna do it all over again. But you want the tutors to do it all over again...? :shock: If you have done all the work, then you should have answers. What then is your question for us? Thank you. Eliz. jonboy 06-21-2006, 05:55 PM Hello Paulinaaa! 1: A piece of paper 11 inches long is ripped into 3 pieces. The first piece is 3 inches more that twice the third piece. The second piece is 3 times the length of the third piece. What is the length of the second piece? Ok, our objective is to get an equation w/just one variable to solve. Ok? So we can derive from the data: x+y+z=11 In which x=1st shred, y=the second shred, z=third shred. The first piece is 3 inches more that twice the third piece= x=2z+3 The second piece is 3 times the length of the third piece= y=3z So fill in our first equation for each with our other 2 equations: x+y+z=11 (2z+3)+(3z)+(z)=11 Solve. Once you calculate z, plug it in for the corresponding element in the equation to find your answer. 10: A flag on a golf course is in the shape of a right triangle. The area of the flag is 156 square inch and its base is 12 inch, find the height of the flag. The area of a Triangle is \frac{bh}{2} \frac{bh}{2} \frac{12h}{2}=156 You can solve this. 11: Angles A and B are complementary angles because their sum is 90 degrees. The measure of angle A is six degrees more than two times the measure of angle B. Find the measure of angle B. Once again you have another system of equations. :D a+b=90 (In which a=m\angle a, b=m\angle b) a=2b+6 So just fill in the a into your first equation and solve making: 2b+6+b=90 14: A class is planning a trip to the Aquarium. They have saved$567 during the year for their annual field trip. Student tickets cost $12 and non-student tickets cost$15. If the number of students visiting the aquarium must be four times the number of non-student chaperones, how many students can visit the museum?
Another system of equations. 8-) Just remember whenever completeting these types of problems to always write out the equations you know cuz it will make it "click" on what to do.

So we can derive 2 equations once again:

12s+14x=567 In which s equals number of student tickets and x is equal to the number of non-student tickets.

s=4x

Now just plug in 4x into the s in our first equation since it is egalitarian to it, making the equation have one variable to solve, thus making an equation that is solvable.

Hence:

12\(4x)+14x=567

15: Kim and Deb ride bicycles in opposite directions. Deb's speed is three miles per hour faster than Kim. If they are 16.5 miles apart in 1.5 hours, what is the speed of Kim?
Based on this info you can derive 2 systems of equations:

d=k+3 (d=Deb's speed, k=Kim's speed)

Ok since distance=speed\bullet{time} you can conclude that:

Deb's distance=d\bullet1.5

Kim's distance=d-3\bullet{1.5}

Add these two equation together to get one "master" equation.

1.5+1.5d-4.5=3d-4.5

Now how far apart the two? Right 16.5 miles.

So now you have two equations:

3d-4.5=16.5
d=k+3

happy
06-21-2006, 10:04 PM
You didn't have to do it all, Jonboy. Let's see what Paulinaaa can do. :wink:

jonboy
06-21-2006, 10:19 PM
You didn't have to do it all, Jonboy. Let's see what Paulinaaa can do. :wink:

Yeah I may have overdone it but I kinda got bored but dont worry I dont do that everyday. I left the solving parts for Paulinaaa to do. She/He probably is already done with the problems and by the time Paulinaaa checks will already be done.

Paulinaaa
06-21-2006, 11:13 PM
Thanks Jonboy..you really did help me! thank you.