what is the polynomial equal to when completly factored

N

nae

New member
Joined
Jun 18, 2006
Messages
33
please help me understand this?

12mb-9m+8b-6

I know i group them (4mb-3m) +(4b-3)

would it be 4m(b-3)?

if not could someone please help me understand.
 
Hello nae:

The trick is to get what is inside the parentheses the same.

\(\displaystyle \L\\12mb-9m+8b-6\)

Factor:

\(\displaystyle \L\\3m(4b-3)+2(4b-3)\)

See there?. 4b-3 inside the parentheses. So, you have:

\(\displaystyle \L\\(3m+2)(4b-3)\)
 
nae said:
please help me understand this?

12mb-9m+8b-6

I know i group them (4mb-3m) +(4b-3)

would it be 4m(b-3)?
Click to expand...
How do you "know" you are to group them like that?

(4mb-3m) +(4b-3) = m*(4b-3) +(4b-3) = (m+1)(4b-3)

You can understand this better if you think about this

m*a + m = m*a + m*1 = m(a+1)
 
repost

nae said:
I know i group them (4mb-3m) +(4b-3)
Click to expand...
Yes; this was explained in your other thread on this exercise.

In the future, please post follow-ups and replies to the original threads. Thank you.

Eliz.
 
You must log in or register to reply here.
Top