Help me solve x/(3y)=(2+z)/z I'm solving for z

[joshholland]

The problem is x/(3y)=(2+z)/z I'm solving for z

I know the answer is z=6y/(x-3y) but I can't figure out how....Please help...I'm desperate


Thanks

[Denis]

x / (3y) = (2+z) / z

start by criss-cross multiplication:
xz = 6y + 3yz
subtract 3yz from each side:
xz - 3yz = 6y

Can you finish it?