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joshholland
06-23-2006, 10:30 PM
The problem is x/(3y)=(2+z)/z I'm solving for z

I know the answer is z=6y/(x-3y) but I can't figure out how....Please help...I'm desperate


Thanks

Denis
06-23-2006, 10:44 PM
x / (3y) = (2+z) / z

start by criss-cross multiplication:
xz = 6y + 3yz
subtract 3yz from each side:
xz - 3yz = 6y

Can you finish it?