quadratic formula: can it be used to solve x^2 = 3?

nae

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Jun 18, 2006
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The quadratic formila cannot be used to solve the following: x^2=3 true or false
i say it's true because there's no way you can use the qudratic formula.

Is this correct.
 
nae said:
The quadratic formila cannot be used to solve the following: x^2=3 true or false
i say it's true because there's no way you can use the qudratic formula.

Is this correct
x^2 + bx + c = 0

In your case b = q0q.

x = [-b+/-sqrt(0 + 12)]/2

x = =/-sqrt3/2 = 1.73205
 
x = =/-sqrt3/2 = 1.73205

So you don't get confused (TchrWill forgot a "2"):

x = +/- 2sqrt(3) / 2
 
As long as \(\displaystyle a\) is not equal to zero and can be expressed using \(\displaystyle ax^2+bx+c=0\) then it can be solved by using the Quadratic Formula.
 
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