Re: true or false: p^2+6p+4=0 can be solved by factoring or.
nae said:
This equation can be solved by using either the factoring method or the quadratic formula p^2+6p+4=0 ? true or false i think it's true you can use the factoring method but not the quadratic is this correct?
If you think that \(\displaystyle \bold p^2+6p+4=0\) can be solved by just using the factoring method, then the answer would be false because both factoring and quadratic methods have to be solvable w/\(\displaystyle p^2+6p+4=0\) since or means both are efficient.
Just work it out and see:
Is there any number that multiply to give you 4 and add up to six?
2*2=4, 2+2=4 which is unequivalent to 6
4*1=4 4+1=5 which is unequivalent to 6
So NO you cannot solve this equation by using the factoring method.
But the Quadratic Method:
\(\displaystyle x=\frac{{ - b \pm \sqrt {b^2 - 4ac} }}{{2a}}\)
\(\displaystyle x=\frac{{ - 6 \pm \sqrt {6^2 - 4(1)(4)} }}{{2(1)}}\)
\(\displaystyle x=\frac{{ - 6 \pm \sqrt {20} }}{2}\)
\(\displaystyle x\approx.8 &\approx - 8.2\)
Since you can put \(\displaystyle \bold p^2+6p+4=0\) in the form \(\displaystyle ax^2 + bx + c = 0\) in which a is not=0, yes it can be factored by using the Quadratic Formula.
So would the answer be False or True?