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LMande
07-07-2006, 11:19 PM
2/x^2 + 3/x + 1/x+2

I'm supposed to add then simplify.

This is what I have so far..

I factored the denominator since it's an exponent.

2/(x+2)(x+1) + 3/x + 1/x+2

Is the common denominator X or x + 2 or am I WAY off?

Any help would be greatly appreciated.

stapel
07-08-2006, 12:35 AM
What you have posted means the following:

. . . . .\L \frac{2}{x^2}\,+\,\frac{3}{x} \,+\,\frac{1}{x}\,+\,2

Is this what you meant? Or did you mean the following:

. . . . .\L \frac{2}{x^2}\,+\,\frac{3}{x}\,+\, \frac{1}{x\,+\,2}

...or something else?

Also, are you using "X" and "x" to mean the same thing? (This would be contrary to mathematical practice, is why I ask.)

Thank you.

Eliz.

Denis
07-08-2006, 01:31 AM
Whoops...hit submit button twice :(

Denis
07-08-2006, 01:35 AM
2/x^2 + 3/x + 1/x+2
I'm supposed to add then simplify.
This is what I have so far..
I factored the denominator since it's an exponent.
2/(x+2)(x+1) + 3/x + 1/x+2
Is the common denominator X or x + 2 or am I WAY off?
Any help would be greatly appreciated.
Assuming you meant: 2/x^2 + 3/x + 1/(x+2) : that set of brackets is IMPORTANT

How in heck did you change x^2 to (x+2)(x+1) ?
(x+2)(x+1) = x^2 + 3x + 2 :shock:

Tuff luck: common denominator is x(x^2)(x+2)

[2(x(x+2)) + 3(x^2(x+2) + 1(x(x^2)] / [x(x^2)(x+2)]

Multiply 'em out, then simplify.

LMande
07-08-2006, 11:31 AM
Okay...

Eliz... it's the second one, but when I realized what it looks like typed out right it should be

(2/x^2 + 2x) + (3/x) + (1/x+2)

I hope I'm typing this in right. I'm really having a hard time "translating" this in computer language!!!