View Full Version : Simplifying -2^4 x 2 + (-2)^4

LaZy1

07-08-2006, 05:10 PM

I'm given the equation -2^4 x 2 + (-2)^4 I work the equation and I keep getting a 48 but the answer, I'm told, is supposed to be -16. Is there a rule or a little tidbit I've forgotten?

I finished and haven't done anything involving algebra for about 2 years now and I've graduated since then, so I'm a bit rusty and forget little things. Thanks for anyone that helps me with this.

\L

\begin{array}{l}

- 2^4 \times 2 = - 32 \\

\left( { - 2} \right)^2 = 16 \\

\end{array}

TchrWill

07-09-2006, 11:00 AM

I'm given the equation -2^4 x 2 + (-2)^4 I work the equation and I keep getting a 48 but the answer, I'm told, is supposed to be -16. Is there a rule or a little tidbit I've forgotten?

I finished and haven't done anything involving algebra for about 2 years now and I've graduated since then, so I'm a bit rusty and forget little things. Thanks for anyone that helps me with this.

(-2)x(-2) = + 4

(+4)x(-2) = -8

(-8)x(-2) = +16

Therefore,, (-2)^4 = +16

16x2 = 32

32 + 16 = 48

I agree with you.

stapel

07-09-2006, 11:12 AM

I agree with you.

Note the parentheses: -2<sup>4</sup> = -(2)(2)(2)(2) = -16 is quite different from (-2)<sup>4</sup> = (-2)(-2)(-2)(-2) = +16.

Eliz.

TchrWill

07-09-2006, 12:38 PM

Note the parentheses: -2<sup>4</sup> = -(2)(2)(2)(2) = -16 is quite different from (-2)<sup>4</sup> = (-2)(-2)(-2)(-2) = +16.

So right you are. Thanks for making me aware of my misdirection.

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