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tristatefabricatorsinc
07-09-2006, 08:07 PM
Simplify the following...

sqrt(18x^3 y^5)
-------------------
sqrt(2xy^2)

can I take the x^3 in the numerator and subtract it with the x^2 in the denominator, or do I have to work on the square root first? I have not done this in a while...

Thank You.

tristatefabricatorsinc
07-09-2006, 08:21 PM
Would I be correct by doing it this way...

by reducing it to...

sqrt(9x^2y^3)

and then...

3xy as the final answer?

galactus
07-09-2006, 08:21 PM
Think of the radical as a 1/2 power.

\L\\\frac{(18x^{3}y^{5})^{\frac{1}{2}}}{(2xy^{2})^ {\frac{1}{2}}}

=\L\\\sqrt{\frac{18x^{3}y^{5}}{2xy^{2}}}

When you divide exponents, you subtract the powers.

Work inside the radical first.

Example: \frac{18x^{3}}{2x}=9x^{2}....See?.

Continue:

\L\\\sqrt{\frac{18x^{3}y^{5}}{2xy^{2}}}\Rightarrow {({9x^{2}y^{3}})^{\frac{1}{2}}}

\L\\3xy^{\frac{3}{2}}

tristatefabricatorsinc
07-09-2006, 09:04 PM
Did you use texAide to make graphical images of the equations, or did you use something else?

galactus
07-09-2006, 09:34 PM
I just typed in the LaTex code.

tristatefabricatorsinc
07-09-2006, 09:51 PM
Ok, I will have to learn it, is it difficult?

galactus
07-10-2006, 07:01 AM
No, click on quote at the upper right corner of my post to see the code.

You can also use TexAide, then copy and paste into your post.

There are many tutorials on the web.

JakeD
07-10-2006, 07:07 AM
Ok, I will have to learn it, is it difficult?
Here is a good tutorial (http://www.sosmath.com/CBB/viewforum.php?f=16) on another math help site.

jonboy
07-10-2006, 09:43 AM
Ok, I will have to learn it, is it difficult?
Here is a good tutorial (http://www.sosmath.com/CBB/viewforum.php?f=16) on another math help site.
Here is the place to download TexAide: link (http://www.dessci.com/en/products/texaide/) (which can be nice for long equations like typing the Quadratic Formula, etc.) and you can also use it as a learning tool by copying and pasting formulas you type and by seeing how the code works .