View Full Version : Beginning Algebra: find interest, with S = 12,600, R = 0.12,
I need help with the math problem below. Is the operation I used correct? Is my answer correct? What is the problem asking? For example, in I = PRT, I know I'm being asked to find the interest. But in the problem below, what does "A" stand for?
A = S / (1 + RT)
with S = 12,600, R = .12, and T = 5/12)
First, I changed 5/12 into a decimal (2.4). Then I multiplied .12 x 2.4 = 0.288. Then I added 1 + 0.288 = 1.288. Then I divided 12600 by 1.288 = 9782.61. So "A" = 9782.61
tkhunny
07-13-2006, 04:57 PM
I think we do not have the entire problem statement. Is there more information in the section heading, maybe?
Denis
07-13-2006, 05:25 PM
I need help with the math problem below. Is the operation I used correct? Is my answer correct? What is the problem asking? For example, in I = PRT, I know I'm being asked to find the interest. But in the problem below, what does "A" stand for?
A = S
__
1 + RT (S = 12,600, R = .12, T = 5/12)
First, I changed 5/12 into a decimal (2.4). Then I multiplied .12 x 2.4 = 0.288. Then I added 1 + 0.288 = 1.288. Then I divided 12600 by 1.288 = 9782.61. So "A" = 9782.61
Get someone to show you how to post properly!
5/12 = .416666.. , NOT 2.4
Your problem SEEMS to be finding the present value A
of 12600 at rate of 12% annual due in 5 months (5/12 of a year).
A = 12600 / (1 + .12(5/12))
A = 12600 / 1.05
A = 12000
tkhunny
07-13-2006, 11:00 PM
A = S / (1 + RT)
with S = 12,600, R = .12, and T = 5/12
First, I changed 5/12 into a decimal (2.4).
Why did you do that?
0.12 * (5/12) = (12/100)*(5/12) = 5/100 = 0.05 -- No rounding needed.
No need to make it harder than it is.
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