Quadratic Equations: book says y(y - 7) = 2y^2 - 14y

J

John Whitaker

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My book tells the following:
Multiply y-7=0 by y and the result is 2y^2-14y=0
Multiply x-6=0 by x and the result is x^2-6x=0

One result shows a coefficient of 2; the other result does not. The equations are nearly identical in structure, so, in the result of the first one, where does the coefficient "2" come from in 2y^2 ? OR, why isn't there a coefficitent of 2 preceeding x in the result of the second statement?
Thank you.
John Whitaker
 
Re: Quadratic Equations

John Whitaker said:
My book tells the following:
Multiply y-7=0 by y and the result is 2y^2-14y=0
Multiply z-6=0 by x and the result is x^2-6x=0

One result shows a coefficient of 2; the other result does not. The equations are nearly identical in structure, so, in the result of the first one, where does the coefficient "2" come from in 2y^2 ? OR, why isn't there a coefficitent of 2 preceeding x in the result of the second statement?
Thank you.
John Whitaker
Click to expand...

Wow you really messed up typing that or something.

If you take \(\displaystyle \L 2x\) times \(\displaystyle \L x-7=0\) then the result is \(\displaystyle \L 2x^2-14x=0\)

If you take \(\displaystyle \L x-6=0\) times \(\displaystyle \L x\) then the result is \(\displaystyle \L x^2-6x=0\)
 
Re: Quadratic Equations

John Whitaker said:
My book tells the following:
"Multiply y-7=0 by y and the result is 2y^2-14y=0"

(y - 7) times y = y^2 - 7y

"Multiply x-6=0 by x and the result is x^2-6x=0"

That's correct
Click to expand...
Is it THAT BOOK again, John :shock:
 
Denis,
(y - 7) times y = y^2 - 7y

That's the answer I get... and yes, it's THAT BOOK! It says:

Multiply y-7=0 by y and the result is 2y^2-14=0... I swear, that's what is printed. Tell me the book is wrong. That's all I need. Thanks. John
 
John Whitaker said:
Denis,
(y - 7) times y = y^2 - 7y
That's the answer I get... and yes, it's THAT BOOK! It says:
Multiply y-7=0 by y and the result is 2y^2-14=0... I swear, that's what is printed. Tell me the book is wrong. That's all I need. Thanks. John
Click to expand...

THE BOOK IS WRONG :idea:

Probably a typo; should be : (y - 7) times 2y

By the way, are you saying "I swear" or "$%#@!&^%*#" :wink:
 
I spent 2 hours staring at that darn thing. I was embarrassed to bring it to the forum, but finally saw no choice. THE BOOK IS WRONG AND I FOUND IT!!! HORAAY!!! "Painless Algebra" by Lynette Long, Ph.D. 1998 edition, p. 207.
Thanks again. I'm done. John
 
Denis,

By the way, are you saying "I swear" or "$%#@!&^%*#"

Sir. I am a gentleman! (But how would you know that... and I could be lying.) I take an oath, it's what the book displays. John
 
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