dy/dt = (y-1)(3-y)
find exact solution with inital condition y(0) = 5
I worked this problem using partial fraction and got
0.5 ln (y-1) + 0.5ln (3-y) = t + c
i tried to plug in that initial condition and its getting no where, any help would be awesome, thanks
find exact solution with inital condition y(0) = 5
I worked this problem using partial fraction and got
0.5 ln (y-1) + 0.5ln (3-y) = t + c
i tried to plug in that initial condition and its getting no where, any help would be awesome, thanks