Solve: 4log_b (x) = log_b (16) so: log_b (x) = 6^4 x = 65536 ?
N NEHA Junior Member Joined Oct 27, 2006 Messages 90 Nov 15, 2006 #1 Solve: 4log_b (x) = log_b (16) so: log_b (x) = 6^4 x = 65536 ?
skeeter Elite Member Joined Dec 15, 2005 Messages 3,215 Nov 15, 2006 #2 no ... \(\displaystyle \L 4\log_b{x} = \log_b{16}\) \(\displaystyle \L \log_b{x^4} = \log_b{16}\) \(\displaystyle \L x^4 = 16\) now finish.
no ... \(\displaystyle \L 4\log_b{x} = \log_b{16}\) \(\displaystyle \L \log_b{x^4} = \log_b{16}\) \(\displaystyle \L x^4 = 16\) now finish.
N NEHA Junior Member Joined Oct 27, 2006 Messages 90 Nov 15, 2006 #3 skeeter said: no ... \(\displaystyle \L 4\log_b{x} = \log_b{16}\) \(\displaystyle \L \log_b{x^4} = \log_b{16}\) \(\displaystyle \L x^4 = 16\) now finish. Click to expand... thank you so much answer is 2 2^4 = 16
skeeter said: no ... \(\displaystyle \L 4\log_b{x} = \log_b{16}\) \(\displaystyle \L \log_b{x^4} = \log_b{16}\) \(\displaystyle \L x^4 = 16\) now finish. Click to expand... thank you so much answer is 2 2^4 = 16