Given points A and B, find eqn for all points equidistant

here's a clue for you ...

the set of points equidistant from two distinct points in a plane lie on the perpendicular bisector of the line segment connecting the two given points.

isn't it amazing how geometry and algebra are connected? :shock:
 
Math wiz ya rite 09 said:
...the points A(9-4, 5) and B(1, 2).
There appears to be a typo in point A, unless you mean that A is (x, y) = (5, 5).

You could use the Distance Formula. Plug A and (x, y) into the Formula. Plug B and (x, y) into the Formula. Set the two expressions equal (since the distances are supposed to be equal) and square both sides.

Solve for "y=". The answer (as mentioned previously) should be a straight line equation, "y = mx + b". If you have to give the answer in the form of a point, then give it in "P = (x, mx + b)" form.

Eliz.
 
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