Okay, question two, (I'm glad I heard about this site, now I can actually understand what I'm learning!) Solve for x any in the system:
3x + 4y = 8
y = 3x + 17
So solve first for x:
3x + 4y = 8
3x = 8 - 4y
(this is where my question lies, when I divide 3 from the left side do you divide it using the 8 or the -4y?
The next step would be to substitute x=(what I came up with) in the second equation.
3x + 4y = 8
y = 3x + 17
So solve first for x:
3x + 4y = 8
3x = 8 - 4y
(this is where my question lies, when I divide 3 from the left side do you divide it using the 8 or the -4y?
The next step would be to substitute x=(what I came up with) in the second equation.