I am not sure how to get started!
Calculate the discriminant and state how many real solutions each equation has:
4x<sup>2</sup> - 6x + 4 = 0
To find the discriminant, you use b<sup>2</sup> - 4ac:
(-6)<sup>2</sup> - 4(4)(4) = -28
Does that mean there is no real solutions, since it's negative?
Thank you
Edited because I was working on it all wrong!
Calculate the discriminant and state how many real solutions each equation has:
4x<sup>2</sup> - 6x + 4 = 0
To find the discriminant, you use b<sup>2</sup> - 4ac:
(-6)<sup>2</sup> - 4(4)(4) = -28
Does that mean there is no real solutions, since it's negative?
Thank you
Edited because I was working on it all wrong!