log problem: log a [power(5)sqrt(a^7) times x^6]/(y^2/5)

Jade

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Sep 16, 2006
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log a [power(5)sqrt(a^7) times x^6]/(y^2/5)

log a x=12
log a y=-1

I hope this is understandable...

This is what I have commuted so far....

log a(a^7/5 times x^6) - log a y^2/5

then log a (a^7/5) + log x^6 - log a (y^2/5)[/list][/code]
 
Jade said:
log a [power(5)sqrt(a^7) times x^6]/(y^2/5)
Is the first "a" the base of the log, so you mean "log_a" (that is, "log<sub>a</sub>")...?

Is the "power (5)" the index of the root, so "power(5)sqrt(a^7)" means "the fifth root of a<sup>7</sup>", so the "sqrt" isn't really a square root...? Or does this mean something else...?

The "times x^6" seems to be included within the logarithm. Is the rest of the expression also inside the log, or is the denominator outside of the argument...?

Does "y^2/5" mean "y<sup>2/5</sup>" or "(y<sup>2</sup>)/5" or something else...?

Are you given that log<sub>a</sub>(x) = 12 and log<sub>a</sub>(y) = -1, or are these your solutions...?

Please reply with clarification, including the instructions. Thank you.

Eliz.
 
Clarification

Yes a is the base of the log

It is the 5th power of the radical a^7

so the (5th power of the radical a^7) multiplied by (x^6) divided by (y^2/5)

So yes your first guess concerning the y^2/5 is correct
 
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