log (10,000) = ? / find (h o g)(-1) for g = x^2 + 3x, h = (x

ChadH

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Nov 18, 2006
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4
My first problem is:

1) log (10,000) = ?

Is the correct answer 4?

The other one is:

2) Given g(x) = x<sup>2</sup> + 3x and h(x) = (x + 3) / 2, find (h o g)(-1)

HUH? Is all I gotta say!
 
Re: Log Questions

ChadH said:
My first problem is:

log (10,000)=?

In the correct answer 4?
log(10000) = log(10^4) = 4*log(10) = 4*1 = 4

g(x)=x<sup>2</sup>+3x
h(x)=(x+3)/2

Find (h o g)(-1)
g(-1) = (-1)^2 + 3(-1) = 1 - 3 = -2
h(-2) = ((-2) + 3)/2 = 1/2

Have you been sleeping in class?
 
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