A number consists of two digits which add up to 9. When the digits are reversed, the original number is decreased by 45. What is the original number?
So here's what I've done:
10A + B = C
A + 10B = C - 45
-10(10A + B = C)
A + 10B = C - 45
-100A - 10B = -10C
so i get
99A = 9C - 45
11A = 1C - 5
After this step I have been trying all different ways but getting no where. Do you have to make a second elimination equation with now only C and B or something? Please can some one help me finish this one up or/and point out any misstakes I've made.
So here's what I've done:
10A + B = C
A + 10B = C - 45
-10(10A + B = C)
A + 10B = C - 45
-100A - 10B = -10C
so i get
99A = 9C - 45
11A = 1C - 5
After this step I have been trying all different ways but getting no where. Do you have to make a second elimination equation with now only C and B or something? Please can some one help me finish this one up or/and point out any misstakes I've made.