logrithm Q: log (little b)c^3 - log (little b)d^4 sqrt t)

wilc0919

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Oct 13, 2006
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write as a sum, difference, or multiple of logarithms:


I don't know how to make the correct notations so here it goes:

the problem says:

log (with a little b hanging underneath) (c^3 / d^4 square root f)

I get to log (little b)c^3 - log (little b)d^4 square root f

am I correct?
 
wilc0919 said:
log (with a little b hanging underneath)...
Have logarithms not yet been covered in class...? (They should have made you familiar with the concepts and terms, including "base of a log", is why I ask.)

The basic log rules are as follows:

. . . . .log<sub>b</sub>(xy) = log<sub>b</sub>(x) + log<sub>b</sub>(y)

. . . . .log<sub>b</sub>(x/y) = log<sub>b</sub>(x) - log<sub>b</sub>(y)

. . . . .log<sub>b</sub>(x<sup>n</sup>) = n log<sub>b</sub>(x)

You appear to have applied the second rule. Now you need to apply the first rule to the second log. Then apply the third rule to the various exponents. Hint: The square root is the one-half power.

Eliz.
 
Is this correct?

With your help I get:

3 log(base b) C - 4 log (base b) D B^1/2

Is that right?
 
wilc0919 said:
I get:

3 log(base b) C - 4 log (base b) D B^1/2

Is that right?
Only if the power 4 is on both the d and the sqrt[f]. Otherwise, you would need to follow the instructions, provided earlier, in order to do the expansion.

Eliz.
 
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