Okay, I am having a lot of trouble with factoring so I'm sure that I will be doing many posts as I continue to work through this unit. Here is my first question:
6 a^2 b^2 + 8 a b^3 = (2•3•a•a•b•b) + (3•3•2•a•b•b•b)
. . . . . . . . . . . . . . . . . .= (2ab•3ab) + (3ab•3b•2b)
. . . . . . . . . . . . . . . . . .= 3ab(2ab + 3b•2b)
. . . . . . . . . . . . . . . . . .= 3ab(2ab + 6b)
Is this how I'm supposed to do this problem?
•Makita
6 a^2 b^2 + 8 a b^3 = (2•3•a•a•b•b) + (3•3•2•a•b•b•b)
. . . . . . . . . . . . . . . . . .= (2ab•3ab) + (3ab•3b•2b)
. . . . . . . . . . . . . . . . . .= 3ab(2ab + 3b•2b)
. . . . . . . . . . . . . . . . . .= 3ab(2ab + 6b)
Is this how I'm supposed to do this problem?
•Makita