factoring to solve equations

janekommer

New member
Joined
Nov 9, 2006
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4
I am getting stuck at the following point in where to go next with this problem.

original problem is 3x^2=8-10x

3x^2-3x^2=8-10x+3x^2

0=8-10x+3x^2

(x+2)(x+5) This is where I got stuck. Did I do this correct?


Am I setting this up correct or should I be factoring the numbers to go to the left?
 
3x^2=8-10x rewrite
3x^2+10x-8=0 solve by factoring [if possible]

factors 3 = 1,3
factors of 8 = 1,8 2,4
we want a set whose difference of products =10
1,3 2,4 does it
[x-4][3x+2]=0
x=4 or 3x+2=0
x=4 or x=-2/3
Arthur
 
[x-4][3x+2]=0

Think you typoed the signs, Arthur; (x + 4)(3x - 2) = 0
 
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