icyhot2590
New member
- Joined
- Mar 18, 2007
- Messages
- 22
find the general solution of the differential solution
dy/dx = (2x^3 + 6)/y
dy/dx= [2x^3+6] / y
y [dy/dx]= [2x^3+6]
y dy =[2x^3+6] dx
y^2 /2 = 2x^4/4 +6x
y^2=x^4 +12x
y^2=x[x^3+12]
i got this far but i still need to find the general solution.... is it y^2 - x^4 +12x =c
dy/dx = (2x^3 + 6)/y
dy/dx= [2x^3+6] / y
y [dy/dx]= [2x^3+6]
y dy =[2x^3+6] dx
y^2 /2 = 2x^4/4 +6x
y^2=x^4 +12x
y^2=x[x^3+12]
i got this far but i still need to find the general solution.... is it y^2 - x^4 +12x =c