mathstresser
Junior Member
- Joined
- Jan 28, 2006
- Messages
- 134
Find the inverse Laplace transforms of the function given
\(\displaystyle \L\\ 1/s^5 - (5-9s)/(s^2 + 100)\)
I get
\(\displaystyle \L\\ (t^4)/24\)
but I don’t know what to do for the second half
the only thing I can come up with is
\(\displaystyle \L\\ [s^2 + 100] = [s^2 + 10^2]\)
but I don’t think that helps much.
\(\displaystyle \L\\ 1/s^5 - (5-9s)/(s^2 + 100)\)
I get
\(\displaystyle \L\\ (t^4)/24\)
but I don’t know what to do for the second half
the only thing I can come up with is
\(\displaystyle \L\\ [s^2 + 100] = [s^2 + 10^2]\)
but I don’t think that helps much.