Help solving 2nd order diff eq.

Miniputtz

New member
Joined
Feb 27, 2006
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6
I need help with this problem.

\(\displaystyle y'' + 6y' + 18y = 180\).

I know how to solve the homogeneous part, I got \(\displaystyle e^{-3x}(C_1Cos(3x)+C_2Sin(3x))\). Is that right?

But I don't know how to get \(\displaystyle Y_p\).
 
\(\displaystyle \L\\y=C_{1}e^{-3x}cos(3x)+C_{2}e^{-3x}sin(3x)+10\)
 
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