8-bits mantissa and 5 bits exponent

I did a floating point addition using 8-bits mantissa and 5 bits exponent. The answer I obtain for:

1) 4.5 + 5.0

01001100 , 00100

2) -12.25 - 10.5

10100101, 00001

3) 7.25 - 14.0

00001101, 00001

4) 0.5 + 0.375

00110000, 00001

5) 0.2 + 0.0625

00001100, 00001

Is my solution above correct.

Well, that would seem to depend on what it is you are doing. Since you didn't really tell us anything, it's pretty hard to make a judgment.

Are you just catenating? Are you adding? Is it an XOR thing?

As a good general rule, the ENTIRE problem statement is the most useful deliverable.

what basically I did is to convert the numbers into 8-bits mantissa and 5 bits exponent. Then I did an arithmatic shift from left to right.

1) 4.5 + 5.0

8-bits mantissa (01001100)

5 bits exponent (00100)

solomon_13000 said:

I did a floating point addition using 8-bits mantissa and 5 bits exponent. The answer I obtain for:

1) 4.5 + 5.0

01001100 , 00100

Click to expand...

If I remember from semesters ago... Your exponent bias adapted to 5-bit should be 15 (available bits range from -16 to 15 as opposed to -128 to 127 for 8-bit).

Since 9.5 = 1.0011 * 2^3 your exponent is 3, so your biased exponent is 3+15=18 or in binary: 10010. Your significand/mantissa is 00110000.

Your binary representation looks like 0-10010-00110000. It is a bit odd using the given precision.