Becky4paws
Junior Member
- Joined
- Feb 15, 2006
- Messages
- 63
I am not quite sure I have a grasp on this.
dy/dx = e^y*square root (x+1)
dy/dx = e^y(x+1)^1/2
d/dy e^y = d/dx(x+1)^1/2
integral d/dy e^y = integral d/dx (x+1)
ln[y] = 3/2(x+1)^3/2
dy/dx = e^y*square root (x+1)
dy/dx = e^y(x+1)^1/2
d/dy e^y = d/dx(x+1)^1/2
integral d/dy e^y = integral d/dx (x+1)
ln[y] = 3/2(x+1)^3/2