Becky4paws
Junior Member
- Joined
- Feb 15, 2006
- Messages
- 63
I'm improving...just not quite there on these:
Find the particular solution of the given differential equation the condtion of y=3 when x=2
dy/dx = x/y^2
y^2 d/dy = x d/dx
integral y^2 d/dy = integral x d/dx
=1/3y^3 + C = l/2 x^2 +C
y^3 = 3/2x^2 + 3C-sub3
The book gives the answer of y^3 = 3/2x^2 + 21...how did they come up with C = 21?
Find the particular solution of the given differential equation the condtion of y=3 when x=2
dy/dx = x/y^2
y^2 d/dy = x d/dx
integral y^2 d/dy = integral x d/dx
=1/3y^3 + C = l/2 x^2 +C
y^3 = 3/2x^2 + 3C-sub3
The book gives the answer of y^3 = 3/2x^2 + 21...how did they come up with C = 21?