Spectral solving PDE: d^2u/dx^2 + d^2u/dy^2

kreedman

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Joined
Sep 19, 2007
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I am numarically solving a PDE using a Fourier Spectral method.

Basically it works in 1D:

u(t+dt) = iF(-iz^2dtF(u(t))

where F is my Fourier transform and iF is my inverse fourier transform. z is the wave number and dt the tie step.

so the second derivative coresponds to -iz^2dt (d^2u/dx^2)

How ill this look like in 2D? when I have:

d^2u/dx^2 + d^2u/dy^2

in my PDE?
 
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