y' +3y =e^(-t) y(0)=-1/2 y=(e^-t)/(2-e^-3t) I can not get this one to work out
D dmdtaz New member Joined Jan 27, 2008 Messages 3 Feb 3, 2008 #1 y' +3y =e^(-t) y(0)=-1/2 y=(e^-t)/(2-e^-3t) I can not get this one to work out
G galactus Super Moderator Staff member Joined Sep 28, 2005 Messages 7,216 Feb 3, 2008 #2 Re: verify by differentiation What did you try?. What integrating factor did you use?.
stapel Super Moderator Staff member Joined Feb 4, 2004 Messages 16,583 Feb 3, 2008 #3 dmdtaz said: y' +3y =e^(-t) y(0)=-1/2 y=(e^-t)/(2-e^-3t) I can not get this one to work out Click to expand... How so? You differentiated the given expression for y (to find y'), plugged y and y' into the given differential equation, and... then what? Please be complete. Thank you! Eliz.
dmdtaz said: y' +3y =e^(-t) y(0)=-1/2 y=(e^-t)/(2-e^-3t) I can not get this one to work out Click to expand... How so? You differentiated the given expression for y (to find y'), plugged y and y' into the given differential equation, and... then what? Please be complete. Thank you! Eliz.