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lukasz
10-19-2008, 11:08 PM
How to factor out a (1+16t^2)^(-1/2)from (1+16t^2)^(1/2)making it a (1+16t^2)^1

lukasz
10-19-2008, 11:09 PM
How to factor out a (1+16t^2)^(-1/2)from (1+16t^2)^(1/2)making it a (1+16t^2)^1 ?

Loren
10-20-2008, 12:06 AM
\frac{1}{a^{-1/2}} = a^{1/2}

or

\frac{a^{1/2}}{a^{-1/2}}\cdot \frac{a^{1/2}}{a^{1/2}}= ???

I'm not sure why you want to factor.

arthur ohlsten
10-20-2008, 12:43 AM
for simplicity let [1+16t^2]=a
this is not neccessary but might help.

factor [1+16t^2]^1/2
factor a^1/2
multiply by 1=a^1/2 a^(-1/2)
a^1/2{a^1/2 a^(-1/2)}
a^(1/2+1/2) a^(-1/2)
a a^(-1/2) answer

Arthur

lukasz
10-20-2008, 01:21 AM
ok thanks

stapel
10-20-2008, 07:25 AM
Duplicate threads merged.