factoring (1+16t^2)^(-1/2) from (1+16t^2)^(1/2) to get

[lukasz]

How to factor out a (1+16t^2)^(-1/2)from (1+16t^2)^(1/2)making it a (1+16t^2)^1

[lukasz]

How to factor out a (1+16t^2)^(-1/2)from (1+16t^2)^(1/2)making it a (1+16t^2)^1 ?

[Loren]

\frac{1}{a^{-1/2}} = a^{1/2}

or

\frac{a^{1/2}}{a^{-1/2}}\cdot \frac{a^{1/2}}{a^{1/2}}= ???

I'm not sure why you want to factor.

[arthur ohlsten]

for simplicity let [1+16t^2]=a
this is not neccessary but might help.

factor [1+16t^2]^1/2
factor a^1/2
multiply by 1=a^1/2 a^(-1/2)
a^1/2{a^1/2 a^(-1/2)}
a^(1/2+1/2) a^(-1/2)
a a^(-1/2) answer

Arthur

[lukasz]

ok thanks

[stapel]

Duplicate threads merged.