how many real solutions does this nonlinear system have:
[x]2 + [y]2 = 16
the x and y are squared
y=x-3
I've tried to use substitution, but this is not working out.
[x]2 + [x-3]2 = 16
[x]2 + [x]2 - 6x + 9 = 16
2[x]2 - 6x +9 - 16 = 0
2[x]2 - 6x - 7 = 0
if I try to factor out here, does not work?
[x]2 + [y]2 = 16
the x and y are squared
y=x-3
I've tried to use substitution, but this is not working out.
[x]2 + [x-3]2 = 16
[x]2 + [x]2 - 6x + 9 = 16
2[x]2 - 6x +9 - 16 = 0
2[x]2 - 6x - 7 = 0
if I try to factor out here, does not work?