bobbyw

11-04-2008, 01:16 AM

The application goes as follows- "The screen of the TI-84 Plus graphing calculator is nearly rectangular. The length of the rectangle is 2 cm more than the width. If the area of the rectangle is 24 cm[sup:2xfkhg3t]2[/sup:2xfkhg3t].find the length and the width." I know that L x W = Area. I know that given x = the width, than 2x equals the length of the rectangle. I think the equation should go (2x) (x) = 24 cm[sup:2xfkhg3t]2[/sup:2xfkhg3t]. So, given that equation, I use the princple of zero and write, 2x[sup:2xfkhg3t]2[/sup:2xfkhg3t] = 24 and 2x[sup:2xfkhg3t]2[/sup:2xfkhg3t] - 24 = 0. Factoring this out gives me 2(x[sup:2xfkhg3t]2[/sup:2xfkhg3t] - 12). It's at this point that I can't seem to go any further. There's nothing I've used to factor this out anymore and I would like some suggestions, please. Thank you.

I've figured out my problem. It wasn't (2x) (x). It is (2 + x) (x). Thanks anyway :)

I've figured out my problem. It wasn't (2x) (x). It is (2 + x) (x). Thanks anyway :)