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ezwind72
11-06-2008, 04:45 PM
Consider the function ABS(x)=/x/, the absolute value of x.

a. What are the domain & range of ABS(x)?
b. Find ABS(-6)

I am not looking for the solution to this but rather what "/x/, the absolute value of x" means. I would like to try and solve it on my own and then have someone check my answer if possible. Thanks!

pka
11-06-2008, 05:06 PM
The absolute value of a real number is the “distance” (number of units) that the number is from zero. So |0|=0 because zero is 0 units from zero while |2|=2 because 2 is two units from zero. What is |-6|, remember that distance is never negative.

ezwind72
11-06-2008, 05:12 PM
So |-6| =6? And the domain would be {x: x is a real number} and the range would {x: x is a real number, x?0}?

Subhotosh Khan
11-06-2008, 05:23 PM
go to:

http://www.analyzemath.com//Absolute_Va ... y_Abs.html (http://www.analyzemath.com//Absolute_Value_Function/Simplify_Abs.html)

for some interactive lessons.