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wood
05-19-2009, 10:02 PM
simplify using the laws of exponents

x^2 (square root of x + square root of y^3)
Y^3

I'm not sure where to start this question

BigGlenntheHeavy
05-19-2009, 10:13 PM
Is \ this \ what \ you \ want \ to \ simplify: \ \frac{x^{2}[x^{1/2}+y^{3/2}]}{y^{3}}?

wood
05-19-2009, 11:02 PM
no

X^2 (square root of x + square root of y^3)
y^3

BigGlenntheHeavy
05-20-2009, 12:00 AM
How \ about \ this: \ \frac{\sqrt x^{2}}{\sqrt y^{3}} \ ?

wood
05-20-2009, 12:53 AM
no

x^2
y^3

Is the first part of the expression, it is all multiplied by ( square root of x + square root of y^3)

Is there a square root sign on the computer?

BigGlenntheHeavy
05-20-2009, 01:07 AM
Hey \ Wood, \ x^{1/2} = \sqrt x.

wood
05-20-2009, 02:13 AM
ok so,

x^2 all multiplied by( x^1^/^2 + (y^3)^1^/^2
y^3

BigGlenntheHeavy
05-20-2009, 03:17 AM
See my first answer, there is nothing to simplify except combining terms in the numerator.

Subhotosh Khan
05-20-2009, 08:17 AM
If you are using standard MS keyboard then to type square-root sign (?)- type <ALT>251 on the number key-pad with "numlock" key activated.

wood
05-20-2009, 10:23 AM
so the Y^3 that is the denominator in the question is only under X^2 how do I get it to be the denominator for the entire question.

Subhotosh Khan
05-20-2009, 11:02 AM
so the Y^3 that is the denominator in the question is only under X^2 how do I get it to be the denominator for the entire question.

Do you agree with following?

\frac{2}{3}\cdot [2 + 3] \,

=\frac{2}{3}\cdot \frac{[2 + 3]}{1} \,

= \, \frac{2\cdot [2 + 3] }{3\cdot 1}

= \, \frac{2\cdot [2 + 3] }{3}

wood
05-20-2009, 11:20 PM
yes i agree

Subhotosh Khan
05-21-2009, 07:46 AM
how do I get it to be the denominator for the entire question

Those are the same steps.....

wood
05-21-2009, 09:25 PM
so

x^2(x^1^/^2+y^3^/^2)
y^3

2/1*1/2=2/2=1

x + x^2y^3^/^2
Y^3

is this my final answer?

Denis
05-22-2009, 12:56 AM
so the Y^3 that is the denominator in the question is only under X^2 how do I get it to be the denominator for the entire question.
Woody, you haven't been listening!
If you have a/b * c, the b is already the FULL denominator: same as ac / b

AND what are you doing here: x^2y^3^/^2 ?
Do you mean y^(3/2)?

If your teacher is trying to teach how to simplify, he/she should be shot at sunrise
for picking such a ridiculous expression :shock: