PDA

View Full Version : simplify x^2/Y3 (square root of x + square root of y^3)

wood
05-19-2009, 09:02 PM
simplify using the laws of exponents

x^2 (square root of x + square root of y^3)
Y^3

I'm not sure where to start this question

BigGlenntheHeavy
05-19-2009, 09:13 PM
Is \ this \ what \ you \ want \ to \ simplify: \ \frac{x^{2}[x^{1/2}+y^{3/2}]}{y^{3}}?

wood
05-19-2009, 10:02 PM
no

X^2 (square root of x + square root of y^3)
y^3

BigGlenntheHeavy
05-19-2009, 11:00 PM
How \ about \ this: \ \frac{\sqrt x^{2}}{\sqrt y^{3}} \ ?

wood
05-19-2009, 11:53 PM
no

x^2
y^3

Is the first part of the expression, it is all multiplied by ( square root of x + square root of y^3)

Is there a square root sign on the computer?

BigGlenntheHeavy
05-20-2009, 12:07 AM
Hey \ Wood, \ x^{1/2} = \sqrt x.

wood
05-20-2009, 01:13 AM
ok so,

x^2 all multiplied by( x^1^/^2 + (y^3)^1^/^2
y^3

BigGlenntheHeavy
05-20-2009, 02:17 AM
See my first answer, there is nothing to simplify except combining terms in the numerator.

Subhotosh Khan
05-20-2009, 07:17 AM
If you are using standard MS keyboard then to type square-root sign (?)- type <ALT>251 on the number key-pad with "numlock" key activated.

wood
05-20-2009, 09:23 AM
so the Y^3 that is the denominator in the question is only under X^2 how do I get it to be the denominator for the entire question.

Subhotosh Khan
05-20-2009, 10:02 AM
so the Y^3 that is the denominator in the question is only under X^2 how do I get it to be the denominator for the entire question.

Do you agree with following?

\frac{2}{3}\cdot [2 + 3] \,

=\frac{2}{3}\cdot \frac{[2 + 3]}{1} \,

= \, \frac{2\cdot [2 + 3] }{3\cdot 1}

= \, \frac{2\cdot [2 + 3] }{3}

wood
05-20-2009, 10:20 PM
yes i agree

Subhotosh Khan
05-21-2009, 06:46 AM
how do I get it to be the denominator for the entire question

Those are the same steps.....

wood
05-21-2009, 08:25 PM
so

x^2(x^1^/^2+y^3^/^2)
y^3

2/1*1/2=2/2=1

x + x^2y^3^/^2
Y^3