simplify x^2/Y3 (square root of x + square root of y^3)

wood

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May 18, 2009
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9
simplify using the laws of exponents

x^2 (square root of x + square root of y^3)
Y^3

I'm not sure where to start this question
 
Re: calculus

\(\displaystyle Is \ this \ what \ you \ want \ to \ simplify: \ \frac{x^{2}[x^{1/2}+y^{3/2}]}{y^{3}}?\)
 
Re: calculus

no

X^2 (square root of x + square root of y^3)
y^3
 
Re: calculus

no

x^2
y^3

Is the first part of the expression, it is all multiplied by ( square root of x + square root of y^3)

Is there a square root sign on the computer?
 
Re: calculus

ok so,

x^2 all multiplied by( x^1^/^2 + (y^3)^1^/^2
y^3
 
Re: calculus

See my first answer, there is nothing to simplify except combining terms in the numerator.
 
Re: calculus

If you are using standard MS keyboard then to type square-root sign (?)- type <ALT>251 on the number key-pad with "numlock" key activated.
 
Re: calculus

so the Y^3 that is the denominator in the question is only under X^2 how do I get it to be the denominator for the entire question.
 
Re: calculus

wood said:
so the Y^3 that is the denominator in the question is only under X^2 how do I get it to be the denominator for the entire question.

Do you agree with following?

\(\displaystyle \frac{2}{3}\cdot [2 + 3] \,\)

\(\displaystyle =\frac{2}{3}\cdot \frac{[2 + 3]}{1} \,\)

\(\displaystyle = \, \frac{2\cdot [2 + 3] }{3\cdot 1}\)

\(\displaystyle = \, \frac{2\cdot [2 + 3] }{3}\)
 
so

x^2(x^1^/^2+y^3^/^2)
y^3

2/1*1/2=2/2=1

x + x^2y^3^/^2
Y^3

is this my final answer?
 
Re: calculus

wood said:
so the Y^3 that is the denominator in the question is only under X^2 how do I get it to be the denominator for the entire question.
Woody, you haven't been listening!
If you have a/b * c, the b is already the FULL denominator: same as ac / b

AND what are you doing here: x^2y^3^/^2 ?
Do you mean y^(3/2)?

If your teacher is trying to teach how to simplify, he/she should be shot at sunrise
for picking such a ridiculous expression :shock:
 
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