View Full Version : Motion problem

This might not be prealgebra but I am not sure how to solve this problem.

Can someone explain what you must do to get the answer to these type of questions?

Photo:

http://f.imagehost.org/0976/motion_math_problem.jpg

Petenerd

06-10-2009, 09:51 PM

Try the forumla d=rt. Meaning, distance equals rate times time. So 50 = (141.5476)(t). Divide 141.5476 on both sides. 50 divide 141.5476 should give you the answer in hours.

Petenerd

06-10-2009, 10:33 PM

I believe so.

sandman369

06-12-2009, 04:28 AM

Since you already got the answer to the nearest hundreth, I figured I would just add on for posterity...

time = \frac{distance}{rate} = \frac{50mi}{141.5476mph} = 0.353238063 hours

Since it says round to the nearest thousandth, you would want to write 0.353 as your answer.

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