italianprincess6807

06-17-2009, 08:15 PM

I need help with this question:

A retacngular dog pen is enclosed with 82 feet of fencing. If the width is 3 feet longer than length, what are the dimensions of the dog pen?

I know the formula is P=2L+2W

I put so far 82=2(3+L)+2W after that I don't even think that is right. Anybody that understands this can you please help me to understand how to do this.

I appreciate it.

Thanks

A retacngular dog pen is enclosed with 82 feet of fencing. If the width is 3 feet longer than length, what are the dimensions of the dog pen?

I know the formula is P=2L+2W

I put so far 82=2(3+L)+2W after that I don't even think that is right. Anybody that understands this can you please help me to understand how to do this.

I appreciate it.

Thanks