italianprincess6807
New member
- Joined
- Jun 17, 2009
- Messages
- 1
I need help with this question:
A retacngular dog pen is enclosed with 82 feet of fencing. If the width is 3 feet longer than length, what are the dimensions of the dog pen?
I know the formula is P=2L+2W
I put so far 82=2(3+L)+2W after that I don't even think that is right. Anybody that understands this can you please help me to understand how to do this.
I appreciate it.
Thanks
A retacngular dog pen is enclosed with 82 feet of fencing. If the width is 3 feet longer than length, what are the dimensions of the dog pen?
I know the formula is P=2L+2W
I put so far 82=2(3+L)+2W after that I don't even think that is right. Anybody that understands this can you please help me to understand how to do this.
I appreciate it.
Thanks