View Full Version : Solve the system using the substittion method
bcroes
06-24-2009, 10:32 PM
Normally these don't get me but I'm stumped.
y=2x=9
y=7x=10
I just end up with tons of fractions and a screwed up solution.
The answer I'm looking for is (-1/5, 43/5) I just don't know how to get there.
Thanks in advance!
Aladdin
06-24-2009, 11:03 PM
Please show us your work, so that we know where to begin to help you
bcroes
06-24-2009, 11:21 PM
Sorry about that...
y = 2x + 9
y = 7x + 10
I know that I need to solve one equation for X so I'll choose the second
y = 7x + 10
-7x + y = 10
-7x = -y +10
x = 1/7y + 10/7
This is where I get confused (that is if the above is even correct)
Taking the first equation I enter 1/7y + 10/7 for X.
y = 2(1/7y + 10/7) + 9
y = 3/7y + 20/7 + 9
y = 3/7y + 83/7
4/7y = 83/7
y = 83/7 * 7/4
y = 581/28
Which can't be correct and is a total disaster. Haha please help me.
Aladdin
06-24-2009, 11:49 PM
Sorry about that...
y = 2x + 9
y = 7x + 10
I know that I need to solve one equation for X so I'll choose the second----> Why,
y = 7x + 10
-7x + y = 10
-7x = -y +10
x = 1/7y + 10/7
This is where I get confused (that is if the above is even correct)
Taking the first equation I enter 1/7y + 10/7 for X.
y = 2(1/7y + 10/7) + 9
y = 3/7y + 20/7 + 9
y = 3/7y + 83/7
4/7y = 83/7
y = 83/7 * 7/4
y = 581/28
Which can't be correct and is a total disaster. Haha please help me.
We may find the value of y in the first equation, which is given y=2x+9 & replace it in the second equation, which gives:
2x+9=7x+10
2x-7x=10-9
-5x=1
Consequently,x=-1/5
For x=-1/5
Then the solution of the system is (-1/5,43/5)
bcroes
06-25-2009, 12:34 AM
That is great! Once again a case of me over analyzing things.
Thank You!
Denis
06-25-2009, 09:24 AM
Paralysis by analysis :wink:
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