cademan

08-19-2010, 03:57 PM

A two-person tent is to be made so that the height at the center is a = 3 feet (see the figure below). If the sides of the tent are to meet the ground at an angle ? = 60°, and the tent is to be b = 8 feet in length, how many square feet of material will be needed to make the tent? (Assume that the tent has a floor and is closed at both ends, and give your answer in exact form.)

Attached is image of tent

[attachment=0:3r9kzfxz]1-1-052alt.gif[/attachment:3r9kzfxz]

Here is my work.... however I may be way out in outfield

So the center pole is 3 ft which if we make X the bottom side,

3 = X*Sqrt(3)

than

3 sqrt(3)/3 = x

than

sqrt(3)=x

So if we make y= Full bottom than since the bottom side is actually double that so 2 sqrt(3)=y

To calculate the area of a triangle we do 1/2 L+H so that would be 6 sqrt(3) one side. Multiply that * 2 sides and we have 12 sqrt(3)

NOw for the rectangles 6 sqrt(3) * 8 = 48 sqrt(3). Multiply that times 3 = 144 q=sqrt(3)

Add those together and I get 156 sqrt(3)

Attached is image of tent

[attachment=0:3r9kzfxz]1-1-052alt.gif[/attachment:3r9kzfxz]

Here is my work.... however I may be way out in outfield

So the center pole is 3 ft which if we make X the bottom side,

3 = X*Sqrt(3)

than

3 sqrt(3)/3 = x

than

sqrt(3)=x

So if we make y= Full bottom than since the bottom side is actually double that so 2 sqrt(3)=y

To calculate the area of a triangle we do 1/2 L+H so that would be 6 sqrt(3) one side. Multiply that * 2 sides and we have 12 sqrt(3)

NOw for the rectangles 6 sqrt(3) * 8 = 48 sqrt(3). Multiply that times 3 = 144 q=sqrt(3)

Add those together and I get 156 sqrt(3)