View Full Version : intermediate algebra - word problems (linear equations, 2 unknowns)

samara3939

09-29-2011, 06:40 PM

a landscaping company placed two orders with a nursery. the first order was for 13 bushes and 4 trees, and totaled &487. the second

order was for 6 bushes and 2 trees, and totalled &232. the bills do not list the per-item price. what were the costs of one bush and one

tree ? (has to be resolved using systems of linear equations. with 2 equations and method of solution)

ok, i understand now that i need some showing of the work. can you help me to start this at least. please let me know if you think i am

posting this in the wrong section. thanks for viewing it and maybe i am lucky and someone will help a little or a lot. thanks you guys ;-)

Mrspi

09-29-2011, 09:47 PM

a landscaping company placed two orders with a nursery. the first order was for 13 bushes and 4 trees, and totaled &487. the second

order was for 6 bushes and 2 trees, and totalled &232. the bills do not list the per-item price. what were the costs of one bush and one

tree ? (has to be resolved using systems of linear equations. with 2 equations and method of solution)

ok, i understand now that i need some showing of the work. can you help me to start this at least. please let me know if you think i am

posting this in the wrong section. thanks for viewing it and maybe i am lucky and someone will help a little or a lot. thanks you guys ;-)

You haven't shown us any work.....

I'll see if I can get you started.

Let b = cost of one bush

Let t = cost of one tree

Ok...you know that the bill for 13 bushes and 4 trees was $487. So,

13b + 4t = 487

Now...can you make an equation for the second bill?

And when you have TWO equations in two variables, you have a system of equations that you can solve. I ASSUME that solving systems is something you've been studying in class.

We need to see some effort on your part, and some indication of where you are "stuck."

samara3939

09-30-2011, 12:42 AM

thanks so much for your help. i went to the math lab and had all my problems resolved with a tutor. will keep you in mind for next time.......thank you very very much.

aadilsabri

10-14-2011, 04:30 AM

for using algebra word problem (http://math.tutorvista.com/algebra/algebra-word-problems.html) Let b = cost of one bush

Let t = cost of one tree

13 bushes and 4 trees was $487. So,

6 bushes and 2 trees, and totalled &232.

13b + 4t = 487 then replace the coefficient of( t ) and divided the4t= 487/13

so use second equation by using 6b+2t=232 then 2t=232/6

mmm4444bot

10-15-2011, 02:09 AM

will keep you in mind for next time

Please read the post titled "Read Before Posting", for next time, too. :cool:

mmm4444bot

10-15-2011, 02:22 AM

13b + 4t = 487

4t = 487/13 ← This equation is not correct

6b + 2t = 232

2t = 232/6 ← This equation is not correct

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