Help with exponent rules!

Have you seen any lessons on properties of exponents? Do you have a textbook? If so, we would like to see your efforts thus far. Or, explain what you do not understand about the examples you've studied. Specific questions are best.

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Cheers :cool:
 
There are only two "exponent rules":
\(\displaystyle a^xa^y= a^{x+ y}\) and
\(\displaystyle (a^x)^y= a^{xy}\)

Have you tried applying those?
 
There are only two "exponent rules": . . . <--- Heck no!
\(\displaystyle a^xa^y= a^{x+ y}\) and
\(\displaystyle (a^x)^y= a^{xy}\)

For appropriate a, b, and c:

\(\displaystyle (a \cdot b)^c = a^cb^c\)

\(\displaystyle \dfrac{a^b}{a^c} = a^{b - c}\)

\(\displaystyle a^0 = 1, \ \ a \ne 0 \ \ and\)

\(\displaystyle 0^a = 0, \ \ a > 0\)

are some other exponent rules.
 
Hmmm, peculiar. When I approved this thread for posting, I saw (and checked) only one link to flickr. Now, I see two links, but the original post has not been edited. Perhaps this is another system error...

Anyway, your work for exercise 3(a) is correct. Good job.



Exercise 3(c) may be done the same way; consider each base individually. That is, think of the given expression like these individual ratios:

\(\displaystyle \frac{6}{4} \cdot \frac{m}{m^9} \cdot \frac{n^3}{n^{11}}\)



Exercise 3(b) has the correct answer, but there are errors in your work.

3(b).JPG

In the first step, you simplified the numerator to get 2. That's correct, but in the denominator you wrote 2^(-5). That is incorrect; the denominator ought to be 2^(-3).

In the second step, you wrote the exponent as 1(-3). That means multiplication, but what you want is subtraction: 1-(-3).

Cheers :cool:
 
For other users, the text in the graphics is as follows:
For (1) and (3), use exponent rules to simplify and express each of the following as a single expression.

\(\displaystyle \mbox{1-a) }\, 8^5\, \times \,8^8\)

\(\displaystyle \mbox{1-b) }\, \left[4^8\right]^5\)

\(\displaystyle \mbox{1-c) }\, (-4)^8 (-4)^9\)

\(\displaystyle \mbox{1-d) }\, 9^4\, \div\, 9^{-8}\)

\(\displaystyle \mbox{1-e) }\, \left(\frac{1}{4}\right)^3 \, \times \, \left(\frac{1}{4}\right)^2\)

\(\displaystyle \mbox{1-f) }\, 5^{-9}\, \div\, 5^{-8}\)

\(\displaystyle \mbox{1-g) }\, \frac{(-20)^3}{(-20)^6}\)

\(\displaystyle \mbox{1-h) }\, \left[(-2)^7\right]^5\)

\(\displaystyle \mbox{3-a) }\, \frac{6^6\, \times \, 6^{-3}}{6^8\, \times\, 6^{-6}}\)

\(\displaystyle \mbox{3-b) }\, \frac{2^5\, \times\, 2^{-4}}{2^{-3}}\)

\(\displaystyle \mbox{3-c) }\, (6mn^3)(4m^9n^{11})\)

\(\displaystyle \mbox{3-d) }\, \frac{(-4)^9\, \times\, (-4)^5}{\left[(-4)^3\right]^4}\)

5) Recall that the relationship between gravitational acceleration and period for a 1.0-m long pendulum is \(\displaystyle T\, =\, 2 \pi g^{-\frac{1}{2}},\) where \(\displaystyle T\) is the period, in seconds, and \(\displaystyle g\) represents the gravitational acceleration, in meters per second squared (m/s^2).

a) The gravitational acceleration at the surface of Mars is about 3.7 m/s^2. Find the period.

b) The period of a 1.0-m long pendulum on the surface of Venus is approximately 2.1 s. Determine the gravitational acceleration, \(\displaystyle g,\) on the surface of Venus.

6) All living organisms contain both carbon-12, which does not decay, and radioactive carbon-14, which decreases exponentially. The decay process can be modelled using the function \(\displaystyle P(t)\, =\, 100\left(\frac{1}{2}\right)^{\frac{t}{5730}},\) where \(\displaystyle P\) represents the percent of carbon-14 remaining and \(\displaystyle t\) represents the time, in years. What percentage of the original carbon-14 remains in the fossils after 2500 years?
 
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