Skelly4444
Junior Member
- Joined
- Apr 4, 2019
- Messages
- 63
I am having trouble obtaining the vector equation of a plane that contains 2 known lines. The lines intersect at the point (1,-3,14).
The question asks for the Cartesian equation of the plane that contains these 2 lines and I'm not able to understand where I'm going wrong.
L1 (7,-3,2) + t(-1,0,2) and L2 (1,1,26) + s(0,1,3)
I follow the procedure to obtain 2 vectors from the 3 known points that lie in the plane, but when I do a vector product on these 2 vectors to obtain a normal vector, I get an answer that is nowhere near the correct one. The answer in the book is 2x -3y +z = 25
Any guidance would be appreciated as I'm completely baffled.
The question asks for the Cartesian equation of the plane that contains these 2 lines and I'm not able to understand where I'm going wrong.
L1 (7,-3,2) + t(-1,0,2) and L2 (1,1,26) + s(0,1,3)
I follow the procedure to obtain 2 vectors from the 3 known points that lie in the plane, but when I do a vector product on these 2 vectors to obtain a normal vector, I get an answer that is nowhere near the correct one. The answer in the book is 2x -3y +z = 25
Any guidance would be appreciated as I'm completely baffled.