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oh okay! thank you!

the standard form of

5-2y=3x

is

-3x-2y+5=0

am i correct?

ahhhhhhhhh! i understand it perfectly now! thank you so much! all of you!
:D

shouldnt i be solving for x if im
1)writing the equation in standadrd form
2)determining the x intercept
3)determining the y intercept
?
well heres what ive done so far

the original problem...

okay, so first of all, i think im getting this roght this time,....how many times have i said that? anyways.

i have figured that the standard is

4x-3y-6=0

so

x= 3/4 y + 6/4

:?: really? well can you thoroughly :!: explain the original problem to me, which is

8x-3y=6-4x

supposed to find x and y intercept

oh, okay! :D that makes a little bit more sense, so i gave it another try and heres what i got this time

y= 1 1/3 x -2

x= 1/4 y + 1/2

and this time, im pretty sure of myself....though i...

well, this is what i got, but i think im still wrong, and still confused...but this is what i got when i moved everything to the other side of the equal side.

y=-2 2/3 x + -2 - 1 1/3 x

did i...

yeah i know that, i just cant get it right....can you help me out....give an explanation perhaps?

well, the instructions say to determine whether each equation is a linear equation, so i have to write this in standard form, along with determining the x and y intercept

i need major help bc i am not understanding this at all...its very confusing...and i am usually awesome at math....heres an example of what im working with

8x-3y=6-4x